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Mechanics problem? |
A ->->-> B A cyclist travels from A to B. At A she is travelling at 8m/s. She descends a vertical distance of 20m to the bottom of the hill from A. The road eventually rises 12m vertically to B. At B she is travelling at 5m/s. She and the bike have a mass of 80 kg. The total distance along the road from A to B is 500m. There is a constant resistance of 20N. What is the work done from A to B? At B the road is horizontal. She is accelerating at 0.5m/s/s. What is the power generated by her at B? Love to help you but your question and its details are very muddled. Is this the actual wording of a question you have been set? tell it much clearly Do your own homework :> Why is this a mechanics problem? Power generated is 7 bhp per millisecond, providing the wind is behind her, and she is ringing her bell to clear the route ahead. a) dW = F(dot)ds W = 20*500 -80*9.8*(20-12) Nm (change signs for work done ON the bike&rider) b) P = (80*0.5 + 20)*5 Nm/s Your questionn not clear. At one point you say at B she travelling at 5m/sec. In the same breath you say at B she is accelerating at .5/m/sec^2.Which one is true? she is travelling at uniform rate or accelerating? |
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