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Math problem!!! i need help!!!? |
Professor Edwards leaps on his mountain bike to get a sandwich. He travels 30 minutes at 30 km/hr, 15 minutes at 40km/hr, 5 minutes at 0km/hr(when he gets his sandwich), and 1 hour at 25 km/hr. What is the total distance he traveled and average velocity? 1/2 *30 + 1/4*40 + 1/12*0 + 1*25= 50 km His time is 1/2 + 1/4 + 1/12+ 1 = 1 hour 50 min so 50 km/(1.83333) = 27.27 km/hr Source(s): http://www.mathassignment.com using the formua: distance = speed X time (first you need to convert all your times into hours by dividing by 60)0.25 hours 30/60= 0.5hours 15/60= 0.25 hours 5/60= 0.083 hours d= (30 x 0.5) + (40 x 0.25) + (0 x 0.0083) +(1 x 25) d= 15+ 10 + 0 + 25 d= 50km 50hm = total distance 1.833= total time then rearrange the formula to get: speed= distance/time speed= 50/1.833 speed= 27.3km/h I think it's 50 km.. if he travels 30 km an hour but he only travels that distance for 30 minutes means he only went 15 km. He went 40 km an hour but since he only went 15 minutes that means he did 1/4 of an hour so 1/4 of 40 which is 10 km and so on. The average velocity I think is 27.27 because he traveled 50 km in 110 minutes. 50km/110 min X 60 min/ 1 hr = 27.27 km per hour 30 minutes at 30 km/hr => 15km 15 minutes at 40km/hr==>10km 5 minutes at 0km/hr====>0km 1 hour at 25 km/hr======>25km so total distance 50km time it took ( including the 5 minute sandwich break ) 110 minutes so average is 50/110 km / minute wich is 60 * 50 / 110 km per hour |
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