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More Math Help! Sorry.?


Answer these question and it's madeup problems So not on test!

x=6 1/9=3 2/3
7/8a for A=2/5
12 3/4 + X =15 7/8
c-1/5=1/2

Word Probelms

Mike rides his biyclce 6 1/2 min 2 school.Cami rides her bike 1 1/2 times as long.How long does it take it 2 get Cami 2 ride to school?

A race course is 3/4 mi long.Racers want 2 run three equal sprints.How far apart should the markers be 4 the sprints?

The sum of Keshi's and Brent's heights is 127 1/4 in Keish's height is 64 1/2 in. Write an equation 2 find Brent's height!

1.) Is this problem written right. Because you say x=6, but there is no x in 1/9= 3 2/3

2.) 7/20

3.) 28 5/8

4.) c= 7/10

5.) 9.75 mins or 9 3/4 mins.

6.) 1/4 mil. apart

7.) 127 1/4 - 64 1/2 = x (x=Brents height)
your lazy, why cant you do this yourself, or ask your parent, or ask your teacher, or stay after for exta help or ask a sibling or ask a friend in that clas??
problem 1. I don't really see an equation, or at least not one that can be solved
problem 2. 7/8 * 2/5 = 7/20
problem 3. 15 7/8 - 12 3/4 = x
x = 3.125
x = 3 1/8
problem 4. c = 1/2 + 1/5
c = 7/10


Word problems
6.5 * 1.5 = 9.75, It takes Cami 9 3/4 minutes to ride to school

3/4 of a mi = 3960 feet
3960 / 3 = 1320 feet
The markers should be placed 1320 feet apart

127 1/4 - 64 1/2 = x
x = 62.75 in
Brent is 62 3/4 in tall.
x=6 1/9=3 2/3
Assuming the 1st = should be +,
x = 11/3 - 55/9

7/8a for A=2/5
(78)(2/5) = 7/20, or
(7/(8(2/5)) = 35/40

12 3/4 + X =15 7/8
X = 3 + 7/8 - 3/4 = 3 1/8

c - 1/5=1/2
c = 1/2 + 1/5 = 7/10

Word Probelms

Mike rides his biyclce 6 1/2 min 2 school.Cami rides her bike 1 1/2 times as long.How long does it take it 2 get Cami 2 ride to school?

(1.5)(6.5) = 9.75 min

A race course is 3/4 mi long.Racers want 2 run three equal sprints.How far apart should the markers be 4 the sprints?

(3/4)(1/3) = 1/4 mi

The sum of Keshi's and Brent's heights is 127 1/4 in Keish's height is 64 1/2 in. Write an equation 2 find Brent's height!

h + 64 1/2 = 127 1/4
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