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I need help with a 10th grade math word problem?



Wheels "R" Us sells bicycles, tricycles, and unicycles. They have one more bicycle than unicycle in stock. If there are 60 pedals and 80 wheels, how many bicycles, tricycals, and unicycles are there in stock ????

u = unicycles (1 wheel)
b = bicycles (2 wheels)
t = tricycles (3 wheels)

b = u + 1 (b/c there's one more bicycle than unicycle)

Each -cycle has 2 pedals, so 30 total -cycles
u + b + t = 30
u + (u+1) + t = 30
2u + t = 29 --------------- t = 29 - 2u

80 total wheels, so
1u + 2b + 3t = 80
u + 2(u+1) + 3t = 80
u + t = 26 ----------------- t = 26 - u


set the 2 equations for t equal to each other
29 - 2u = 26 - u
u = 3

unicylces = 3
bicycles = 3 + 1 = 4
tricycles = 30 - 3 - 4 = 23
Bicycles have two wheels. If we use B to indicate how many bicycles, there are 2*B wheels and 2*B pedals on them.
Tricycles have three wheels. If we use T to indicate how many tricycles, there are 3*T wheels and 2*T pedals on them.
Unicycles have one wheel. If we use U to indicate how many unicycles, there are U wheels and 2*U pedals on them.

The total wheels is 2*B + 3*T + U = 80
The total pedals is 2*B + 2*T + 2*U = 60, which means that B+T+U=30, if we divide both sides by 2.

We also know that there is one more B than U, so..
B = U + 1

So...
2*(U+1) + 3*T + U = 80
(U+1) + T +U = 30

(2*U + 2) + 3*T + U = 80
U + 1 + T + U = 30

3*T + 3*U = 78
T + 2*U = 29

T + U = 78 / 3 = 26
T + 2*U = 29
U = 3
T = 29 - 2*3 = 23

B = U + 1 = 4

There are 4 bicycles with 8 wheels and 8 pedals
There are 23 tricycles with 69 wheels and 46 pedals
There are 3 unicycles with 3 wheels and 6 pedals
ow. but i figured out the answer. 12 bikes.13 tricycals,and 16 unicycles.I feel sorry for you though.HAPPY TO HELP.
MATH WIZ.
i have no fuckin clue
Wow, that hurts my head just thinking about it Good luck.
try a couculator or do it the old fashond way ask your parents
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