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CAn the grads help me on this Physics problems???? |
question 1: A bicyclist exerts a constant force of 40.0N on a pedal 0.15m from the axis of rotation of a penny-farthing bicycle whell witha radius of 50.0cm. If his speed is 2.25m/s after 3.0s, what is the moment of inertia of the wheel?? (Disregard friction and the inertia of the small wheel?) question 2: A bicycle is a combination of simple machines. Identify three types of simple machines used to propel a typical bicycle. Question 1: Torque is a force applied at a distance, T = F * r Where T is the torque, F is the force, and r is the radius the force is applied away from the center or rotation. T = 40 Newtons * .15 meters = 6 Newton meters A torque causes an angular acceration, T = alpha * I where T is the torque, alpha is the angular acceleration, and I is the rotational inertia ("moment of inertia"). An angular acceleration relates to a linear acceleration, alpha = a / R where alpha is the angular acceleration, a is the linear acceleration, and R is the radius of rotation (the wheel's radius in this case). The linear acceleration can be found by finding the change in linear velocity with respect to time, a = delta v / delta t a = 2.25 m/s / 3 s = .75 m/s^2 alpha = .75 m/s^2 / .5 meters = 1.5 radians per second^2 T = alpha * I --> I = T / alpha I = 6 Nm / 1.5 rad/s^2 = 4 kg m^2 Do your own homework next time (like on question 2). http://sln.fi.edu/qa97/spotlight3/spotli... Do your own damn homework. I will teach u my child. Come & meet me in my cabin tommorrow morning.!!! 1. torque = force * radius = 40 * .15 = 6 Nm torque = moment of inertia (I) * ang acc ang acc = acc/radius = velocity/time*acc = 2.25/3 * .75 = 1.5 rad per sec sqr I = 6/1.5 = 4 kg m sqr 2. well two of them are linear motion angular motion |
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