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Can someone show the correct way to work the following problem?



Lori and Jon work in the toy department of the J-Mart discount store. Lori can assemble a bike in x minutes and Jon can assemble a bike in x-16 minutes. Write an algebraic expression for the number of bikes they can assemble if they work together for a ten hour shift.

di ko alam eh...
Lori can assemble 1/x bikes in a minute
=60/x bikes in an hour
=600/x bikes in 10 hours.

Jon can assemble 1/(x-16) bikes in a minute
=60/(x-16) bikes in an hour
=600/(x-16) bikes in 10 hours.

number of bikes they can assemble if they work together for a ten hour shift
=600/x+600/(x-16)
=[600(x-16)+600x]/[x(x-16)]
=[1200(x-8)]/[x(x-16)]
N(1/x + 1/(x - 16)) = 10*60
x +(x-16) = 600
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