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More quadratic function questions..? |
When bikes are sold for $300 each, a cycle store can sell 70 in a season. For every $25 increase in price, the number drops by 10. 1. Represent the sales revenue as a function of the price. 2. The total sales revenue is $17 500. How many bikes were sold? What is the price of one bike? 3. What range of prices will provide a revenue that exceeds $18 000? Thank you! Please explain D: Ok, let's begin with the number sold, that would be for a Price P, n= 70 - 10(P-300)/25 I'm assuming a gradual decline in sales as Price goes up from 300 rather than step function The revenue will be n* P or R= P(70 - 10(P-300)/25 ) to do part 2 set this equal to 17,500 and solve (that's your part of the job) there will be two answers, but you might want to think about why a businessman would want to operate at one point or the other (same profit but very different outcomes in terms of social value and such)... To do part three we need to solve R>= 18000, you can do that (and part 2) by hand, or just graph R and set the window on your graph.. Good luck |
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